Maths Quiz of the Day-II

Maths Quiz of the Day – II For SSC MTS : 23-08-2019

1. O is the circumcenter of the isosceles ΔABC. Given that AB = AC = 10 cm and BC = 12 cm. The radius of the circle is
(A) 6.25 cm
(B) 6.205 cm
(C) 6.125 cm
(D) 3.125 cm

2 2/3 of 2.1 is how much less than 0.2% of 800?
(A) 0.2
(B) 1.46
(C) 14.6
(D) 158.6

3. A certain amount is divided among A, B and C in the ratio of 3:7:6 respectively. If the difference between share of A and B is Rs. 2700, what is C’s share?
(A) Rs. 4050
(B) Rs. 4000
(C) Rs. 4100
(D) Rs. 4500

4. A 3 lit mixture contains two liquid wine and water in which 13% water is present. In the above mixture, another 3 lit mixture which has 8% water, is added and ¼ lit water also added separately then what is the percent age of water.
(A) 17.08%
(B) 14.08%
(C) 16.08%
(D) 12.08%

5. A bank offers 10% compound interest per year. A cus tomer deposits Rs. 3600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is.
(A) Rs 1116
(B) Rs 2232
(C) Rs 558
(D) Rs 279
Direction (6-9): In the Bar-graph data is given about some students who appeared in final exam. Study the data carefully and answer the related questions. Full marks in Math, Science and social science is 100,75 and 150 respectively.

 

6. What is respective ratio of average obtained marks in Math and science of all students together?
(A) 2 : 3
(B) 1 : 2
(C) 2 : 1
(D) None of these

7. Total marks obtained by B is what percent more/less than that of D?
(A) 3%
(B) 4%
(C) 4.34%
(D) 5.67%

8. What is average obtained marks of all students together in science?
(A) 40
(B) 50
(C) 48
(D) 60

9. What is difference between total obtained of A and C?
(A) 10
(B) 15
(C) 30
(D) 40

10. Tanya gave 20% in charity from her salary, and then 20% from the remaining she gave to her friend as loan. She is left now with 6400. What is the salary of Tanya?
(A) 12000
(B) 10000
(C) 10200
(D) 11000

 

Solutions:

 

Ans.1(A)

                        
            AB= AC = 10 cm.
            AD ⊥ BC 
            BD = DC = 6 cm. 

            AD2 = AB2 – BD2

            = 100 – 36 = 64

            AD = 8 cm

            In triangle OCD

            OC2 = OD2 + DC2

            r2 = (8 – r)2  + 36

            r2 = 64 + r2 – 16r + 36

            16r = 100

            r = 100/16 =6.25

Ans.2(A)  Required value  = 1.6 – 1.4 = 0.2

Ans.3(A)  7x – 3x = 2700
             4x = 2700
              x = 675
              C’s Share = 675 × 6 = Rs. 4050

Ans.4(B)   Water in 1st = 3 ×13/100  = 0.39 lit

              Water in 2nd = 3 ×  8/100  = 0.24 lit

              Additional = 0.25 lit

              Total : 0.39 + 0.24 + 0.25 = 0.88 lit

              Total of water =  0.88/(3+3+0.25)=0.88/6.25  ×    100 = 14.08%

Ans.5(A)   Compound Interest on 3600 deposited on 1st Jan at the end of the year at 10% per half year

               = 360 + 360 +36

               Compound Interest on 3600 deposited on 1st Jul at the end of the year at 10% per half year

                = 360

                 Total Compound interest = 1080 + 36 = 1116

                  Note:

                Here interest rate is given on half yearly basis not annually. So we will take rate  of interest  as it is i.e. 10%    while calculating

Ans.6(D)     Required ratio =

                100×((45+70+75+80+90)/500)

                75((60+80+40+60+80)/500)

                Since obtaing marks given in graph is in percentage

                = 4 × 360 : 3 × 320 = 3:2

Ans.7(C)    Total marks of B = 

Ans.8(C)

Ans.9(B)

Ans.10(B)Let the whole money be = 100 x

              20% of 100x = 20x
              After given to charity, Tanya had 
              = 100x – 20x = 80x
              The money given to her friend= 20% of 80x = 16x
              Remaining money 

              = 100x – (20x + 16x) = 64x
                         A.T.Q 

               64x = 6400

                x = 100
               Thus the whole money = 100x = 10000

 

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