Maths Quiz of the Day-I

Maths Quiz of the Day – I For IBPS PO Mains 2019 : 24-08-2019

Directions Q.(1-5) Study the pie chart carefully and answer the questions given below.
Pie – Chart shows the percentage distribution of the number of passengers in different trains.
Total Number of passengers = 72000

Q.1 If in train ‘V’ 42% of the passengers are males and 23% are children, what is the number of females in that train?
(1) 3296
(2) 2880
(3) 3156
(4) 3024
(5) None of these

Q.2 The total number of passengers in train ‘U’ and train ‘R’ together is approximately what percent more than the total number of passengers in train ‘Q’ and train ‘P’ together?
(1) 81%
(2) 77%
(3) 73%
(4) 79%
(5) 76%

Q.3 What is the average number of passengers in train ‘S’ train ‘V’, train ‘T’ and Train ‘P’.
(1) 9540
(2) 9900
(3) 9180
(4) 9000
(5) None of these

Q.4 What is the difference between the total number of passengers in train ‘U’ and train ‘Q’ together and the number of passengers in train ‘R’?
(1) 9260
(2) 9380
(3) 9440
(4) 9160
(5) None of these

Q.5 Number of passengers in train ‘S’ is approximately what percent of the total number of passenger in train ‘T’ and train ‘Q’ together?
(1) 86%
(2) 87%
(3) 83%
(4) 84%
(5) 88%

Directions Q.(6-8) What approximate value should come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value).
Q.6 7687.98÷62+3856.012-?-∛17575 = 24.01×36.99
(1) 3124
(2) 3066
(3) 2936
(4) 3296
(5) 2992

Q.7 4×18.245+7.69% of (756.14-329.96+853.92-√9410) = ?
(1) 146
(2) 186
(3) 198
(4) 164
(5) 136

Q.8 √3842×46.01+ ∛54875-2575.99÷28-?2=298.12
(1) 50
(2) 49
(3) 51
(4) 52
(5) 53

Q.9 (867+926-493) + (1568÷28×17)-?=376
(1) 1914
(2) 1732
(3) 1876
(4) 1798
(5) 1854

Q.10 2/3 of 4/7 of 5/11 of 113883 – ? = 233-173
(1) 12466
(2) 11996
(3) 13369
(4) 12588
(5) 11964

Solutions:

 

Ans.1(4)       Required number of females

                    = 72000x  12/100  x ((100-42-23))/100= 3024

Ans.2(2)       Required % = ((22+17)-(8+14))/((8+14))×100

                   = (39-22)/22 ×100

                   = 1700/22 = 77.27%  77%

Ans.3(1)       Required average = (72000×(16+12+11+14))/100×4 

                   = 9540

Ans.4(5)       Required difference = 72000 ×  ([(22+8)-17])/100

                   = 720×13 = 9360

Ans.5(4)       Required % = 16/((11+8))×100 = 1600/19 = 84.2184%

Ans.6(2)       7688÷62+3856-?-∛17576 = 24×37

                   124+3856-?-26=888

                   3954-888=?

Ans.7(4)       4×18.25 + 1/13 ×(756-330+854-√9409)=?

                   73+  1/13 (1280-97)=?

                   73+  1183/13 = ?

                   73+91=?

                   ?=164

Ans.8(1)       √3844 ×46 + ∛54872 – 2576÷28-?2=298

                   62×46 + 38-92-298=?2

                   2852 – 352=?2

                   ?2 = 2500

Ans.9(3)       1300+(56×17)-376=?

                    ? = 1876

Ans.10(1)     2/3  ×  4/7 ×  5/11 ×113883-?=12167-4913

                   40×493-?=7254

                   19720-7254 = ?

                     12466=?

NO COMMENTS:

Your email address will not be published. Required fields are marked *