Reasoning Quiz of the Day – I For IBPS RRB PO Mains 2019 : 29-08-2019

Reasoning Quiz of the Day-I

Reasoning Quiz of the Day – I For IBPS RRB PO Mains 2019 : 29-08-2019

Directions Q.(1-5): In each question given below three statements are followed by two conclusions numbered I and II. You have to take the three given statements to be true even if they seem to be at variance with the commonly known facts. Read the conclusions and decide which conclusion logically follows from the three given statement disregarding commonly known facts.
Give answer –
(1) Only conclusion I follows.
(2) Only conclusion II follows.
(3) Either conclusion I or II follows.
(4) Neither conclusion I nor II follows.
(5) Both conclusion I and II follow.

Q.1 Statements: All trays are cups. All cups are spoon. Some spoons are pens.
Conclusions: I. All trays are spoons. II. All pens being trays is a possibility.

Q.2 Statements: Some slates are notes. All notes are teachers.
Conclusions: I. All notes being slates is a possibility. II. At least some teachers are slates.

Q.3 Statements: No employee is manager. Some mangers are stupids. Some honest are employees.
Conclusions: I. It is possibility that some honest are stupid. II. It is possibility that all managers are honest.

Q.4 Statements: Some drinks are bottles. Some bottles are meal. All glasses are bottle.
Conclusions: I. Some glasses are drinks. II. All bottles can be glass is a possibility.

Q.5 Statements: Some fruits are buildings. Some buildings are hotels. No hotel is a room.
Conclusions: I. At least some hotels are fruits II. All rooms being buildings is a possibility

Direction Q.(6-10) A word arrangement machine when gives an input line of words rearranges them following a particular rule in each step. The following is an illustration of input and rearrangement.
Input : Yhaurk stijk cadxq zuprv efobl
Step I : Cadxq yhurk stijk zuprv efobl
Step II : 14 efobl yhurk stijk zuprv
Step III : 14 7 stijk yhurk zuprv
Step IV : 14 7 8 14 4

Answer the following questions are based on the following input.
Input : Swder gnokl aesxv uckmf thpbc

Q.6 What will be the sum of number which is first from left end and second from the right end of step IV ?
(1) 36
(2) 38
(3) 21
(4) 22
(5) None of these

Q.7 What will be the step III of given Input ?
(1) 21 gnokl swder ukcmf thpbcf
(2) 21 5 thpbc uckmf
(3) 21 5 1 thpbc uckmf
(4) 21 5 1 17 Uckmf
(5) None of these

Q.8 Which is last step of given input ?
(1) Step III
(2) Step IV
(3) Step V
(4) Step VI
(5) None of these

Q.9 Which is second last word/number in step IV ?
(1) tjhpbc
(2) Uckmf
(3) 15
(4) 17
(5) None of these

Q.10 What is difference between 1st number in step III and last number in step IV ?
(1) 8
(2) 7
(3) 6
(4) 10
(5) None of these

 

Solutions:

Ans.1(5) Here is the Venn diagram representation of the given information-

Both conclusion I and II follow.
Ans.2(5) Here is the Venn diagram representation of the given information-

Both conclusion I and II follow.
Ans.3(5) Here is the Venn diagram representation of the given information

Both conclusions I and II follow.
Ans.4(2) Here is the Venn diagram representation of the given information-

Only conclusion II follows.

Ans.5(2) Here is the Venn diagram representation of the given information-

Only conclusion II follows.
Ans.(6-10) For words-
All words are arranged in alphabetic order. The logic of the arrangement of words is that the word which is first according to the alphabetic series is arranged first from left end in step I, then the word which is second according to the alphabetical order is arranged and also the word which is already arranged is replaced with number which is the difference of the place values of the first and last letter of the word and process continues.
Input : Swder gnokl aesxv uckmf thpbc
Step I : aesxv swder gnokl uckmf thpbc
Step II : 21 gnokl swder uckmf thpbc
Step III : 21 5 1 thpbc uckmf
Step IV : 21 5 1 17 15
Ans.6(2) 21 + 17 = 38
Ans.7(3)
Ans.8(2)
Ans.9(4)
Ans.10(3)
 

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